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Products of Differences over Arbitrary Finite Fields

Abstract

There exists an absolute constant \delta > 0 such that for all qq and all subsets AβŠ†FqA \subseteq \mathbb{F}_q of the finite field with qq elements, if |A| > q^{2/3 - \delta}, then |(A-A)(A-A)| = |\{ (a -b) (c-d) : a,b,c,d \in A\}| > \frac{q}{2}. Any \delta <1/13,542 suffices for sufficiently large qq. This improves the condition |A| > q^{2/3}, due to Bennett, Hart, Iosevich, Pakianathan, and Rudnev, that is typical for such questions. Our proof is based on a qualitatively optimal characterisation of sets A,XβŠ†FqA,X \subseteq \mathbb{F}_q for which the number of solutions to the equation (a1βˆ’a2)=x(a3βˆ’a4) ,β€…β€Ša1,a2,a3,a4∈A,x∈X (a_1-a_2) = x (a_3-a_4) \, , \; a_1,a_2, a_3, a_4 \in A, x \in X is nearly maximum. A key ingredient is determining exact algebraic structure of sets A,XA, X for which ∣A+XA∣|A + XA| is nearly minimum, which refines a result of Bourgain and Glibichuk using work of Gill, Helfgott, and Tao. We also prove a stronger statement for (Aβˆ’B)(Cβˆ’D)={(aβˆ’b)(cβˆ’d):a∈A,b∈B,c∈C,d∈D} (A-B)(C-D) = \{ (a -b) (c-d) : a \in A, b \in B, c \in C, d \in D\} when A,B,C,DA,B,C,D are sets in a prime field, generalising a result of Roche-Newton, Rudnev, Shkredov, and the authors

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This paper was published in Explore Bristol Research.

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